The electric field components are ex ax 1 2

Asked by admin @ in Physics viewed by 502 People

The electric field component in the figure are Ex=800x^2N/C, Ey=Ez=0. calculate

(a)the flux through the cube
(b)the charge within the cube
Assume thate a=0.1m

Answered by admin @


(a) The flux through the cube , ∅ = EA

given, electric field along x - axis is Ex = 800 x² N/C

electric field at origin , E_0= 0 N/C

electric field at x = a , E_a = 800a²

now, The flux through the cube , ∅ = (800a² - 0) × a²

= 800a⁴

= 800 × (0.1)⁴ [ given , a = 0.1 m]

= 8 × 10^-2 Nm²/C

(b) charge within the cube , Q = ∅\epsilon_0= 8 × 10^-2 Nm²/C × 8.85 × 10^-12 C²/Nm²

= 7.08 × 10^-13 C


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