A rocket of mass m is launched straight up with thrust f⃗ thrust.

Asked by maham237 @ 18/12/2020 in Physics viewed by 1304 People

a. Find an expression for the rocket's speed at height h if air resistance is neglected. Express your answer in terms of the variables Fthrust, m, h, and appropriate constants.
b. The motor of a 340 g model rocket generates 10 N thrust. If air resistance can be neglected, what will be the rocket's speed as it reaches a height of 86 m ?

Answered by maham237 @ 18/12/2020

From the statement, since rocket was launched so this means
that it start from zero, hence initial velocity is zero.

Since the rocket was launched vertically straight up, the
force acting on this motion is gravity.

A. The acceleration of the motion is then given
by:

a= F/m - g

Then we can use the general equation:

V^2 = Vo^2 + 2*a*h

where V is final velocity, Vo is initial velocity, a is acceleration,
h is height

Since we know that Vo = 0, so

V^2 = 2*a*h

V^2 = 2 (F/m – g) h

V = sqrt [2 h (F/m – g)]

B. Given that:

h = 86 m

F = 10 N

m = 340 g = 0.34 kg

Find for V:

V = sqrt [2 * 86 (10 / 0.34 – 9.8)]

V = 58.08 m/s

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