A drop of olive oil of radius 0.25 mm

Asked by admin @ 16/08/2021 in Physics viewed by 293 People

Answer this: A drop of olive oil of radius 0.25mm spreads into a circular film of radius 5cm on the water surface. Estimate the molecular size of he olive oil.

Answered by admin @ 16/08/2021

$\huge \mathfrak {Answer:-}$

Area of the film,

$A = \pi \: r ^{2} cm ^{2}$

$A = 25\pi \: cm^{2}$

$\bold{Since,}$

Radius of the film,

$r = 5 \: cm$

$\bold{Now,}$

Volume of the drop, V

$= \frac{4}{3} \pi$ (Radius of the oil drop) $^{3}$

$= \frac{4}{3} \times \pi \times (0.25mm)^{3}$

$= \frac{4}{3} \times \pi \times (2.5 \times 10 ^{ - 1} ) ^{3} mm ^{3}$

$= \frac{4}{3} \times \pi \times 15.6 \times 10^{ - 3} mm ^{3}$

$= \frac{4}{3} \times \pi \times 15.6 \times 10 ^{ - 6} cm^{3}$

Molecular size = Thickness of the film

$= \frac{V}{A}$

$= \frac{4\pi \times 15.6 \times 10 ^{ - 6} }{3 \times 25\pi}$

$= 0.83 \times 10 ^{ - 6} cm$

$= 8.3 \times 10 ^{ - 9} m$

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A drop of olive oil of radius 0.25 mm

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