Which second degree polynomial function f(x) has a lead coefficient of 3 and roots 4 and 1?
Asked by maham237 @ in Mathematics viewed by 434 People
f(x) = 3x2 + 5x + 4
f(x) = 3x2 + 15x + 12
f(x) = 3x2 – 5x + 4
f(x) = 3x2 – 15x + 12
Answered by maham237 @
For this case we have that the following function complies with the given conditions:
To prove it, let's find the roots of the polynomial:
By doing common factor 3 we have:
Factoring the second degree polynomial we have:
Then, the solutions are:
Solution 1:
Solution 2:
Answer:
A second degree polynomial function f (x) that has a lead coefficient of 3 and roots 4 and 1 is:
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