What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth?

Asked by maham237 @ 26/12/2020 in Mathematics viewed by 349 People

What are the approximate solutions of 4x^2 + 3 = -12x to the nearest hundredth?
A.) x ≈ -3.23 and x ≈ 0.23
B.) x ≈ -2.72 and x ≈ -0.28
C.) x ≈ 0.28 and x ≈ 2.72
D.) x ≈ -0.23 and x ≈ 3.23

Answered by maham237 @ 26/12/2020

Add 12x to both sides
4x^2+12x+3=0
we cannot factor
use quadractic formula
for an eqution
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

a=4
b=12
c=3
x= $\frac{-12+/- \sqrt{12^2-4(4)(3)} }{2(4)}$
x= $\frac{-12+/- \sqrt{144-48} }{8}$
x= $\frac{-12+/- \sqrt{96} }{8}$
x= $\frac{-12+/- 4\sqrt{6} }{8}$
x= $\frac{-3+/- \sqrt{6} }{2}$
aprox
x=-2.7247 or -0.2752

B is answer

What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth?

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