Square efgh stretched vertically by a factor of 2.5

Asked by maham237 @ in Mathematics viewed by 253 People

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ?

Answered by maham237 @


Given

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H

The square stretches with respect to the x-axis.

If point H is located at (-2, 0)

Find the coordinates of H′

To proof

In stretching case

when the stretching take place by scale fator

let coordinate = (x,y )

After stetching

new coordinate = ( kx,ky)

As given in question

Square EFGH stretches vertically by a factor of to create square E′F′G′H′= 2.5

square stretches with respect to the x-axis

coordinate of H = (-2,0)

coordinates of H′ = 2.5 (-2,0)

= ( -5 , 0 )

Hence proved









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