Let f(x) = –5x - 4 and g(x) = 6x - 7. find f(x) + g(x).

Asked by maham237 @ 22/12/2020 in Mathematics viewed by 320 People

A. -11x+3
B. x+3
C. -11x-11
D. x-11

2. let f(x)=3x+2 and g(x)=6x-7. find f(x)-g(x)
A. 3x-9
B. -3x+9
C. -3x-5
D. 2x-1

3. let f(x)=-5+3 and g(x)=6x-2. find f*g and its domain
A. -30x^2+28x-6; all real numbers except x=1/3
B. -15x^2-8x-12; all real numbers except x=3/5
C. -30x^2+28x-6; all real numbers
D. -15x^2-8x-12; all real numbers

Answered by maham237 @ 22/12/2020

Question 1:
We have the following functions:
$f(x) = - 5x - 4

g(x) = 6x - 7$
We have then:
For f (x) + g (x):
We add both functions.
We have then:
$f (x) + g (x) = (- 5x - 4) + (6x - 7)

f (x) + g (x) = (- 5x + 6x) + (-4 - 7)

f (x) + g (x) = x - 11$
Answer:
D. x - 11

Question 2:
We have the following functions:
$f(x) = 3x + 2

g(x) = 6x - 7$
We have then:
For f (x) - g (x):
We subtract both functions.
We have then:
$f (x) - g (x) = (3x + 2) - (6x - 7)

f (x) - g (x) = (3x - 6x) + (2 + 7)

f (x) - g (x) = -3x + 9$
Answer:
B. -3x + 9

Question 3:
We have the following functions:
$f(x) = -5x + 3

g(x) = 6x - 2$
We have then:
$f (x)*g (x) = (-5x + 3)*(6x - 2)
$
Rewriting we have:
$f (x)*g (x) = -30x^2 + 10x + 18x - 6

f (x)*g (x) = -30x^2 + 28x - 6$
The domain of the function is all real because it has no restriction.
Answer:
C. -30x^2 + 28x - 6; all real numbers

Let f(x) = –5x - 4 and g(x) = 6x - 7. find f(x) + g(x).

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