How to write the linear equation in slope intercept form

Asked by admin @ 28/10/2021 in Mathematics viewed by 350 People

write a linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) site

Answered by admin @ 28/10/2021

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

$y=\frac{1}{4}x-\frac{9}{4}$

Step-by-step explanation:

Given points are:

(-11, -5) = (x1,y1)

(1, -2) = (x2,y2)

We have to find the slope first

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-2-(-5)}{1-(-11)}\\m=\frac{-2+5}{12}\\m=\frac{3}{12}\\m=\frac{1}{4}$

Slope-intercept form is:

$y=mx+b$

Put the value of slope

$y=\frac{1}{4}x+b$

To find the value of b, putting the point (1 -2) in equation

$-2=\frac{1}{4}(1)+b\\-2=\frac{1}{4}+b\\-2-\frac{1}{4}=b\\b=\frac{-8-1}{4} \\b=\frac{-9}{4}$

Putting the values of b and m

$y=\frac{1}{4}x-\frac{9}{4}$

A linear equation in slope intercept form that passes through the points (-11 -5) and (1 -2) is:

$y=\frac{1}{4}x-\frac{9}{4}$

Keywords: Equation of line, slope-intercept form

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