For what values of x is the expression below defined


Asked by maham237 @ in Mathematics viewed by 518 People


Answered by maham237 @



Answer:

A) -5\leq x < 1

Step-by-step explanation:

First, let's notice that we need positives numbers inside both roots. The root of a negative number is a math error (we are not dealing with complex numbers right now). With that information, let's analyze the options:

A) -5\leq x < 1

If we add 5 in this inequation, we have

-5+ 5\leq x+5 < 1+5

0\leq x+5 < 6

That's means the number in the first root is positive, great!

Now, we want 1-x to be positive:

-5\leq x < 1

5\geq -x > -1 (remember that the inequation changes side when we multiply by a negative number, (-1) in this case)

1+5\geq 1-x > 1-1

6\geq 1-x > 0

It's positive!

This is the correct answer but let's see why the others are incorrect.

B)5> x \leq-1

We just need to find a number that fits the inequation but causes at least one root to have a negative number inside.

For example, -6.

5>-6

-6 \leq -1

But -6+5 = -1 is negative

C) 5 > x > 1

In this case, the number 2 fits the inequation but it causes the second root to have a negative number inside, 1 - 2 = -1

D) 5 \leq x \leq 1

This option can't be correct because there is no number smaller than 1 and bigger than 5.


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