Determine the magnitude of the electric field in this region


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In a certain region, the electric potential due to a charge distribution is given by the equation v(x,y,z) = 3x2y2 + yz3 - 2z3x, where x, y, and z are measured in meters and v is in volts. calculate the magnitude of the electric field vector at the position (x,y,z) = (1.0, 1.0, 1.0).

Answered by admin @



The electric potential due to a charge distribution is given by

 V(x,y,z)=3x^{2}y^{2}+yz^{3}+2z^{3}x (Equation 1)

Differentiating the above equation 1 with respect to x,

 V_{x}=6xy^{2}+2z^{3} (Equation 2)

Differentiating the above equation 1 with respect to y,

 V_{y}=6x^{2}y+z^{3} (Equation 3)

Differentiating the above equation 1 with respect to z,

 V_{z}=3yz^{2}+6z^{2}x (Equation 4)

Substituting the value of x,y and z in equations 2,3 and 4

  V_{x}=6+2=8

 V_{y}=6+1=7

 V_{z}=3+6=9

Magnitude =  \sqrt{8^{2}+7^{2}+9^{2}}

= \sqrt{194}

= 14.0


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