Work done in converting one gram of ice at
Asked by admin @ in Physics viewed by 406 People
work done in converting one gram of ice at minus 10 degree Celsius to steam at hundred degree celsius is
Answered by admin @
Q = mass * Specific heat * ∆ T
For ice, Q = 1 * 2.09 * 10 = 20.9 J
For water, Q = 1 * 4.186 * 100 = 418.6 J
For melting the ice, use the following equation.
Q = mass * Heat of fusion
Heat of fusion 333 J/g
Q = 1 * 333 = 333 J
For boiling the water, use the following equation.
Q = mass * Heat of vaporization
Heat of vaporization = 2260 J/g
Q = 1 * 2260 = 2260 J
Total = 20.9 + 418.6 + 333 + 2260 = 3032.5 J = 3.0325 kg
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