Find the least number which when divided by
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Find the least number which when divided by 6, 15, 18 leave remainder 5 in each case
Answered by admin @
Solution :-
To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.
L.C.M. of 6, 5 and 18
6 = 2*3
15 = 3*5
18 = 2*3*3
L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90
Now,
5 + 90 = 95
Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.
Let us check our answer.
1) 95/6
Quotient = 15
Remainder = 5
2) 95/15
Quotient = 6
Remainder = 5
3) 95/18
Quotient = 5
Remainder = 5
So, the required number is 95.
Answer.
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