Find the image of the point 1 6 3
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Find the image of the point (1,0,0) x/1=y/2=z/3
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Any point ‘O’ on line AB is given by (k, 2k + 1, 3k + 2) So, direction ratio of the line OP are k – 1 , 2k – 5, 3k – 1 . .. (k – 1) × 1 + (2k – 5) × 2 + (3k – 1) × 3 = 0 => 14k – 14 = 0 => k = 1 Hence, co-ordinate of O are (1,3,5) Now, Let image of P(1,6,3) in the given line be Q (α, β , γ) So, ‘O’ is the mid point of PQ So, The image of P is R(1,0,7)Read more on Sarthaks.com - https://www.sarthaks.com/256557/find-the-image-of-the-point-1-6-3-in-the-line-x-1-y-1-2-z-2-3
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