Abc and dbc are on the same base bc
Asked by admin @ in Math viewed by 346 People
ABC and DBC are two triangle on the same base BC .if AD intersect BC at O show that
ar(ABC)/ar(DBC)=AO/DO
Asked by admin @ in Math viewed by 346 People
ABC and DBC are two triangle on the same base BC .if AD intersect BC at O show that
ar(ABC)/ar(DBC)=AO/DO
Answered by admin @
ABC & DBC are two triangles on the same base BC
AD intersects BC at O
Construction:- AP ⊥ BC and DQ ⊥ BC
In Δ APO and Δ DQO, we have
∠APO = ∠DQO = 90° .... [right angles]
∠AOP = ∠DOQ ..... [vertically opposite angles]
∴ Δ APO ~ Δ DQO ...... [By AA similarity]
We know that → the corresponding sides of similar triangles are proportional to each other.
∴ ...... (i)
Now, we have
cancelling the similar terms
from (i), we get
Hence proved
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triangle PQR and triangle SQR are isosceles triangles on the same base . prove that angle PQS = angle PRS.
triangle PQR and triangle QSR lie on same base QR.Also angle PSQ=angle RQS.if ar triangle PQR=12cmsquare,find ar triangle QSR
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