A 2 b 2 c 2 d 2 4abcd


Asked by admin @ in Math viewed by 349 People


(a^2-b^2)(c^2-d^2)-4abcd

Answered by admin @



Hi there,

Solution:-
(a^2-b^2)(c^2-d^2)-4abcd
a²c²-a²d²-b²c²+b²d²-4abcd
a²c²-a²d²-b²c²+b²d²-2abcd-2abcd
a²c²+b²d²-2abcd-a²d²-b²c²-2abcd
(a²c²+b²d²-2abcd)-(a²d²+b²c²+2abcd)
[(ac)²+(bd)²-2abcd]-[(ad)²+(bc)²+2abcd]

We know that,
[x²+y²-2xy=(x-y)²] and
[x²+y²+2xy=(x+y)²]

=>(ac−bd)²−(ad+bc)²

We know that,
[(a²-b²)=(a+b)(a-b)]

=>[ac-bd+(ad+bc)][ac−bd)−(ad+bc)]

=>(ac-bd+ad+ac)(ac-bd-ad-bc) ANSWER...

Hope this helps you:-)))


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