25 25 is divided by 26 the remainder is


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When 25∧25 is divided by 26 , the remainder is

Answered by admin @




Method (1):

Consider, f(x)=x^{25}+1.

As you can see f(-1)=0 which means (x+1) is a factor of f(x).

Hence, f(x)=(x+1)g(x) for some g(x) of degree 24.

Now, 25^{25}=(25^{25}+1)-1=f(25)-1=(25+1)g(25)-1=26(g(25)-1)+25.

Hence, remainder is 25.



Method (2):

From Binomial Theorem,

25^{25}=(26-1)^{25}=^{25}C_{0}(26)^{25}+^{25}C_{1}(26)^{24}(-1)^{1}+.....+^{25}C_{25}(-1)^{25} .

So the last term is "-1". Hence remainder is "26+(-1)" = 25.


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