In an organic compound of molar mass 108
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In an organic compound with molar mass 108 g, c, h, and n are present in the ratio 9: 1: 3.5 by mass. Molecular formula of the compound is:
Asked by admin @ in Chemistry viewed by 282 People
In an organic compound with molar mass 108 g, c, h, and n are present in the ratio 9: 1: 3.5 by mass. Molecular formula of the compound is:
Answered by admin @
Molar mass of compound = 108 grams
Total part by weight = 9 + 1 + 3.5 = 13.5
Weight of carbon = (9*108)/13.5 = 72 g
Number of carbon atoms = 72/12 = 6
Weight of hydrogen = (1*108)/13.5 = 8 g
Number of hydrogen atoms = 8/1 = 8
Weight of nitrogen = (3.5*108)/13.5 = 28 g
Number of nitrogen atoms = 28/14 = 2
Hence, molecular formula is C6H8N2
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