Calculate the mass percentage of benzene and carbon tetrachloride

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Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.

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Hey there!

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Answer :

Given that,

Mass of benzene (C_{6} H_{6}) = 22 g

Mass of carbon tetrachloride (CCl_{4}) = 122 g

Mass of solution dissolved = 22 g + 122 g = 144 g

Then, we have to find,

Mass percentage of benzene = ?

Mass percentage of carbon tetrachloride = ?

Now, using the formula,

∴ Mass percentage of benzene = \frac{ \text{Mass of benzene} }{ \text{Mass of benzene + Mass of carbon tetrachloride} } × 100

⇒ Mass percentage of benzene = \frac{22}{22 + 122} × 100

⇒ \frac{22}{144} × 100

⇒ \frac{11}{72} × 100

⇒ \frac{1100}{72} = 15.2%

→ Mass percentage of benzene = 15.2%

∴ Mass percentage of CCl_{4} = 100 -15.2% = 84.8%

→ Mass percentage of CCl_{4} = 84.8%


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